4(2b)=4b+4(3b-4)

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Solution for 4(2b)=4b+4(3b-4) equation: 



4(2b)=4b+4(3b-4)

We move all terms to the left:

4(2b)-(4b+4(3b-4))=0



We calculate terms in parentheses: -(4b+4(3b-4)), so:

4b+4(3b-4)

We multiply parentheses

4b+12b-16

We add all the numbers together, and all the variables

16b-16

Back to the equation:

-(16b-16)



We get rid of parentheses

42b-16b+16=0

We add all the numbers together, and all the variables

26b+16=0

We move all terms containing b to the left, all other terms to the right

26b=-16

b=-16/26

b=-8/13

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