4(2b)=5(((4b+4(3b-4))/8)

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Solution for 4(2b)=5(((4b+4(3b-4))/8) equation: 



4(2b)=5(((4b+4(3b-4))/8)

We move all terms to the left:

4(2b)-(5(((4b+4(3b-4))/8))=0

We multiply all the terms by the denominator


42b*8))-(5(((4b+4(3b-4))=0

Wy multiply elements

336b^2=0

a = 336; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·336·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{672}=0$

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