4(2b+1)-3(b-5)=7

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Solution for 4(2b+1)-3(b-5)=7 equation: 



4(2b+1)-3(b-5)=7

We move all terms to the left:

4(2b+1)-3(b-5)-(7)=0

We multiply parentheses

8b-3b+4+15-7=0

We add all the numbers together, and all the variables

5b+12=0

We move all terms containing b to the left, all other terms to the right

5b=-12

b=-12/5

b=-2+2/5

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