4(2b+3)=-3(b-1)+31

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Solution for 4(2b+3)=-3(b-1)+31 equation: 



4(2b+3)=-3(b-1)+31

We move all terms to the left:

4(2b+3)-(-3(b-1)+31)=0

We multiply parentheses

8b-(-3(b-1)+31)+12=0



We calculate terms in parentheses: -(-3(b-1)+31), so:

-3(b-1)+31

We multiply parentheses

-3b+3+31

We add all the numbers together, and all the variables

-3b+34

Back to the equation:

-(-3b+34)



We get rid of parentheses

8b+3b-34+12=0

We add all the numbers together, and all the variables

11b-22=0

We move all terms containing b to the left, all other terms to the right

11b=22

b=22/11

b=2

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