4(2b-2)=3(b+2)+1

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Solution for 4(2b-2)=3(b+2)+1 equation: 



4(2b-2)=3(b+2)+1

We move all terms to the left:

4(2b-2)-(3(b+2)+1)=0

We multiply parentheses

8b-(3(b+2)+1)-8=0



We calculate terms in parentheses: -(3(b+2)+1), so:

3(b+2)+1

We multiply parentheses

3b+6+1

We add all the numbers together, and all the variables

3b+7

Back to the equation:

-(3b+7)



We get rid of parentheses

8b-3b-7-8=0

We add all the numbers together, and all the variables

5b-15=0

We move all terms containing b to the left, all other terms to the right

5b=15

b=15/5

b=3

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