4(2b-2)=7+3b

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Solution for 4(2b-2)=7+3b equation:



4(2b-2)=7+3b
We move all terms to the left:
4(2b-2)-(7+3b)=0
We add all the numbers together, and all the variables
4(2b-2)-(3b+7)=0
We multiply parentheses
8b-(3b+7)-8=0
We get rid of parentheses
8b-3b-7-8=0
We add all the numbers together, and all the variables
5b-15=0
We move all terms containing b to the left, all other terms to the right
5b=15
b=15/5
b=3

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