4(2b-3)+(-16)=4(2b-4)

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Solution for 4(2b-3)+(-16)=4(2b-4) equation: 



4(2b-3)+(-16)=4(2b-4)

We move all terms to the left:

4(2b-3)+(-16)-(4(2b-4))=0

We add all the numbers together, and all the variables

4(2b-3)-(4(2b-4))-16=0

We multiply parentheses

8b-(4(2b-4))-12-16=0



We calculate terms in parentheses: -(4(2b-4)), so:

4(2b-4)

We multiply parentheses

8b-16

Back to the equation:

-(8b-16)



We add all the numbers together, and all the variables

8b-(8b-16)-28=0

We get rid of parentheses

8b-8b+16-28=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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