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4(2b-3)+-16=4(2b-4)
We move all terms to the left:
4(2b-3)+-16-(4(2b-4))=0
We add all the numbers together, and all the variables
4(2b-3)-(4(2b-4))=0
We multiply parentheses
8b-(4(2b-4))-12=0
We calculate terms in parentheses: -(4(2b-4)), so:We get rid of parentheses
4(2b-4)
We multiply parentheses
8b-16
Back to the equation:
-(8b-16)
8b-8b+16-12=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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