4(2b-3c)+2(b+6c)=0

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Solution for 4(2b-3c)+2(b+6c)=0 equation:


Simplifying
4(2b + -3c) + 2(b + 6c) = 0
(2b * 4 + -3c * 4) + 2(b + 6c) = 0
(8b + -12c) + 2(b + 6c) = 0
8b + -12c + (b * 2 + 6c * 2) = 0
8b + -12c + (2b + 12c) = 0

Reorder the terms:
8b + 2b + -12c + 12c = 0

Combine like terms: 8b + 2b = 10b
10b + -12c + 12c = 0

Combine like terms: -12c + 12c = 0
10b + 0 = 0
10b = 0

Solving
10b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '10'.
b = 0.0

Simplifying
b = 0.0

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