4(2b-7)=5(8+2b)

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Solution for 4(2b-7)=5(8+2b) equation: 



4(2b-7)=5(8+2b)

We move all terms to the left:

4(2b-7)-(5(8+2b))=0

We add all the numbers together, and all the variables

4(2b-7)-(5(2b+8))=0

We multiply parentheses

8b-(5(2b+8))-28=0



We calculate terms in parentheses: -(5(2b+8)), so:

5(2b+8)

We multiply parentheses

10b+40

Back to the equation:

-(10b+40)



We get rid of parentheses

8b-10b-40-28=0

We add all the numbers together, and all the variables

-2b-68=0

We move all terms containing b to the left, all other terms to the right

-2b=68

b=68/-2

b=-34

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