4(2c+1)+2(3c-6)=10

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Solution for 4(2c+1)+2(3c-6)=10 equation: 



4(2c+1)+2(3c-6)=10

We move all terms to the left:

4(2c+1)+2(3c-6)-(10)=0

We multiply parentheses

8c+6c+4-12-10=0

We add all the numbers together, and all the variables

14c-18=0

We move all terms containing c to the left, all other terms to the right

14c=18

c=18/14

c=1+2/7

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