4(2c+1)=19+3c

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Solution for 4(2c+1)=19+3c equation: 



4(2c+1)=19+3c

We move all terms to the left:

4(2c+1)-(19+3c)=0

We add all the numbers together, and all the variables

4(2c+1)-(3c+19)=0

We multiply parentheses

8c-(3c+19)+4=0

We get rid of parentheses

8c-3c-19+4=0

We add all the numbers together, and all the variables

5c-15=0

We move all terms containing c to the left, all other terms to the right

5c=15

c=15/5

c=3

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