4(2c+1)=3(3c+5)

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Solution for 4(2c+1)=3(3c+5) equation:


Simplifying
4(2c + 1) = 3(3c + 5)

Reorder the terms:
4(1 + 2c) = 3(3c + 5)
(1 * 4 + 2c * 4) = 3(3c + 5)
(4 + 8c) = 3(3c + 5)

Reorder the terms:
4 + 8c = 3(5 + 3c)
4 + 8c = (5 * 3 + 3c * 3)
4 + 8c = (15 + 9c)

Solving
4 + 8c = 15 + 9c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9c' to each side of the equation.
4 + 8c + -9c = 15 + 9c + -9c

Combine like terms: 8c + -9c = -1c
4 + -1c = 15 + 9c + -9c

Combine like terms: 9c + -9c = 0
4 + -1c = 15 + 0
4 + -1c = 15

Add '-4' to each side of the equation.
4 + -4 + -1c = 15 + -4

Combine like terms: 4 + -4 = 0
0 + -1c = 15 + -4
-1c = 15 + -4

Combine like terms: 15 + -4 = 11
-1c = 11

Divide each side by '-1'.
c = -11

Simplifying
c = -11

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