4(2c+1)=3c-18

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Solution for 4(2c+1)=3c-18 equation: 



4(2c+1)=3c-18

We move all terms to the left:

4(2c+1)-(3c-18)=0

We multiply parentheses

8c-(3c-18)+4=0

We get rid of parentheses

8c-3c+18+4=0

We add all the numbers together, and all the variables

5c+22=0

We move all terms containing c to the left, all other terms to the right

5c=-22

c=-22/5

c=-4+2/5

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