4(2c+3)+1=3c+15+5c

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Solution for 4(2c+3)+1=3c+15+5c equation: 



4(2c+3)+1=3c+15+5c

We move all terms to the left:

4(2c+3)+1-(3c+15+5c)=0

We add all the numbers together, and all the variables

4(2c+3)-(8c+15)+1=0

We multiply parentheses

8c-(8c+15)+12+1=0

We get rid of parentheses

8c-8c-15+12+1=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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