4(2c+3)-2=2(4c+5)

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Solution for 4(2c+3)-2=2(4c+5) equation: 



4(2c+3)-2=2(4c+5)

We move all terms to the left:

4(2c+3)-2-(2(4c+5))=0

We multiply parentheses

8c-(2(4c+5))+12-2=0



We calculate terms in parentheses: -(2(4c+5)), so:

2(4c+5)

We multiply parentheses

8c+10

Back to the equation:

-(8c+10)



We add all the numbers together, and all the variables

8c-(8c+10)+10=0

We get rid of parentheses

8c-8c-10+10=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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