4(2c+3)=3(-3c+6)

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Solution for 4(2c+3)=3(-3c+6) equation: 



4(2c+3)=3(-3c+6)

We move all terms to the left:

4(2c+3)-(3(-3c+6))=0

We multiply parentheses

8c-(3(-3c+6))+12=0



We calculate terms in parentheses: -(3(-3c+6)), so:

3(-3c+6)

We multiply parentheses

-9c+18

Back to the equation:

-(-9c+18)



We get rid of parentheses

8c+9c-18+12=0

We add all the numbers together, and all the variables

17c-6=0

We move all terms containing c to the left, all other terms to the right

17c=6

c=6/17

c=6/17

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