4(2c-1)+6=14+6(3c-2)

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Solution for 4(2c-1)+6=14+6(3c-2) equation: 



4(2c-1)+6=14+6(3c-2)

We move all terms to the left:

4(2c-1)+6-(14+6(3c-2))=0

We multiply parentheses

8c-(14+6(3c-2))-4+6=0



We calculate terms in parentheses: -(14+6(3c-2)), so:

14+6(3c-2)

determiningTheFunctionDomain
6(3c-2)+14

We multiply parentheses

18c-12+14

We add all the numbers together, and all the variables

18c+2

Back to the equation:

-(18c+2)



We add all the numbers together, and all the variables

8c-(18c+2)+2=0

We get rid of parentheses

8c-18c-2+2=0

We add all the numbers together, and all the variables

-10c=0

c=0/-10

c=0

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