4(2c-1)-6=4c+6

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Solution for 4(2c-1)-6=4c+6 equation: 



4(2c-1)-6=4c+6

We move all terms to the left:

4(2c-1)-6-(4c+6)=0

We multiply parentheses

8c-(4c+6)-4-6=0

We get rid of parentheses

8c-4c-6-4-6=0

We add all the numbers together, and all the variables

4c-16=0

We move all terms containing c to the left, all other terms to the right

4c=16

c=16/4

c=4

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