4(2c-1)=4(5c-1)

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Solution for 4(2c-1)=4(5c-1) equation: 



4(2c-1)=4(5c-1)

We move all terms to the left:

4(2c-1)-(4(5c-1))=0

We multiply parentheses

8c-(4(5c-1))-4=0



We calculate terms in parentheses: -(4(5c-1)), so:

4(5c-1)

We multiply parentheses

20c-4

Back to the equation:

-(20c-4)



We get rid of parentheses

8c-20c+4-4=0

We add all the numbers together, and all the variables

-12c=0

c=0/-12

c=0

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