4(2c-2)-7=6c+1

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Solution for 4(2c-2)-7=6c+1 equation: 



4(2c-2)-7=6c+1

We move all terms to the left:

4(2c-2)-7-(6c+1)=0

We multiply parentheses

8c-(6c+1)-8-7=0

We get rid of parentheses

8c-6c-1-8-7=0

We add all the numbers together, and all the variables

2c-16=0

We move all terms containing c to the left, all other terms to the right

2c=16

c=16/2

c=8

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