4(2c-3)-3(c-4)=

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Solution for 4(2c-3)-3(c-4)= equation:


Simplifying
4(2c + -3) + -3(c + -4) = 0

Reorder the terms:
4(-3 + 2c) + -3(c + -4) = 0
(-3 * 4 + 2c * 4) + -3(c + -4) = 0
(-12 + 8c) + -3(c + -4) = 0

Reorder the terms:
-12 + 8c + -3(-4 + c) = 0
-12 + 8c + (-4 * -3 + c * -3) = 0
-12 + 8c + (12 + -3c) = 0

Reorder the terms:
-12 + 12 + 8c + -3c = 0

Combine like terms: -12 + 12 = 0
0 + 8c + -3c = 0
8c + -3c = 0

Combine like terms: 8c + -3c = 5c
5c = 0

Solving
5c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '5'.
c = 0

Simplifying
c = 0

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