4(2c-3)=2(6c-6)+4c

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Solution for 4(2c-3)=2(6c-6)+4c equation:


Simplifying
4(2c + -3) = 2(6c + -6) + 4c

Reorder the terms:
4(-3 + 2c) = 2(6c + -6) + 4c
(-3 * 4 + 2c * 4) = 2(6c + -6) + 4c
(-12 + 8c) = 2(6c + -6) + 4c

Reorder the terms:
-12 + 8c = 2(-6 + 6c) + 4c
-12 + 8c = (-6 * 2 + 6c * 2) + 4c
-12 + 8c = (-12 + 12c) + 4c

Combine like terms: 12c + 4c = 16c
-12 + 8c = -12 + 16c

Add '12' to each side of the equation.
-12 + 12 + 8c = -12 + 12 + 16c

Combine like terms: -12 + 12 = 0
0 + 8c = -12 + 12 + 16c
8c = -12 + 12 + 16c

Combine like terms: -12 + 12 = 0
8c = 0 + 16c
8c = 16c

Solving
8c = 16c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-16c' to each side of the equation.
8c + -16c = 16c + -16c

Combine like terms: 8c + -16c = -8c
-8c = 16c + -16c

Combine like terms: 16c + -16c = 0
-8c = 0

Divide each side by '-8'.
c = 0

Simplifying
c = 0

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