4(2c-3)=2(c+18)

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Solution for 4(2c-3)=2(c+18) equation: 



4(2c-3)=2(c+18)

We move all terms to the left:

4(2c-3)-(2(c+18))=0

We multiply parentheses

8c-(2(c+18))-12=0



We calculate terms in parentheses: -(2(c+18)), so:

2(c+18)

We multiply parentheses

2c+36

Back to the equation:

-(2c+36)



We get rid of parentheses

8c-2c-36-12=0

We add all the numbers together, and all the variables

6c-48=0

We move all terms containing c to the left, all other terms to the right

6c=48

c=48/6

c=8

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