4(2c-3)=5(c-2)

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Solution for 4(2c-3)=5(c-2) equation:


Simplifying
4(2c + -3) = 5(c + -2)

Reorder the terms:
4(-3 + 2c) = 5(c + -2)
(-3 * 4 + 2c * 4) = 5(c + -2)
(-12 + 8c) = 5(c + -2)

Reorder the terms:
-12 + 8c = 5(-2 + c)
-12 + 8c = (-2 * 5 + c * 5)
-12 + 8c = (-10 + 5c)

Solving
-12 + 8c = -10 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
-12 + 8c + -5c = -10 + 5c + -5c

Combine like terms: 8c + -5c = 3c
-12 + 3c = -10 + 5c + -5c

Combine like terms: 5c + -5c = 0
-12 + 3c = -10 + 0
-12 + 3c = -10

Add '12' to each side of the equation.
-12 + 12 + 3c = -10 + 12

Combine like terms: -12 + 12 = 0
0 + 3c = -10 + 12
3c = -10 + 12

Combine like terms: -10 + 12 = 2
3c = 2

Divide each side by '3'.
c = 0.6666666667

Simplifying
c = 0.6666666667

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