4(2d+3)=80

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Solution for 4(2d+3)=80 equation: 



4(2d+3)=80

We move all terms to the left:

4(2d+3)-(80)=0

We multiply parentheses

8d+12-80=0

We add all the numbers together, and all the variables

8d-68=0

We move all terms containing d to the left, all other terms to the right

8d=68

d=68/8

d=8+1/2

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