4(2d+7)=2d+25+3(2d+1)

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Solution for 4(2d+7)=2d+25+3(2d+1) equation:


Simplifying
4(2d + 7) = 2d + 25 + 3(2d + 1)

Reorder the terms:
4(7 + 2d) = 2d + 25 + 3(2d + 1)
(7 * 4 + 2d * 4) = 2d + 25 + 3(2d + 1)
(28 + 8d) = 2d + 25 + 3(2d + 1)

Reorder the terms:
28 + 8d = 2d + 25 + 3(1 + 2d)
28 + 8d = 2d + 25 + (1 * 3 + 2d * 3)
28 + 8d = 2d + 25 + (3 + 6d)

Reorder the terms:
28 + 8d = 25 + 3 + 2d + 6d

Combine like terms: 25 + 3 = 28
28 + 8d = 28 + 2d + 6d

Combine like terms: 2d + 6d = 8d
28 + 8d = 28 + 8d

Add '-28' to each side of the equation.
28 + -28 + 8d = 28 + -28 + 8d

Combine like terms: 28 + -28 = 0
0 + 8d = 28 + -28 + 8d
8d = 28 + -28 + 8d

Combine like terms: 28 + -28 = 0
8d = 0 + 8d
8d = 8d

Add '-8d' to each side of the equation.
8d + -8d = 8d + -8d

Combine like terms: 8d + -8d = 0
0 = 8d + -8d

Combine like terms: 8d + -8d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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