4(2d-3)=28

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Solution for 4(2d-3)=28 equation: 



4(2d-3)=28

We move all terms to the left:

4(2d-3)-(28)=0

We multiply parentheses

8d-12-28=0

We add all the numbers together, and all the variables

8d-40=0

We move all terms containing d to the left, all other terms to the right

8d=40

d=40/8

d=5

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