4(2d-3)=5(d-2)

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Solution for 4(2d-3)=5(d-2) equation: 



4(2d-3)=5(d-2)

We move all terms to the left:

4(2d-3)-(5(d-2))=0

We multiply parentheses

8d-(5(d-2))-12=0



We calculate terms in parentheses: -(5(d-2)), so:

5(d-2)

We multiply parentheses

5d-10

Back to the equation:

-(5d-10)



We get rid of parentheses

8d-5d+10-12=0

We add all the numbers together, and all the variables

3d-2=0

We move all terms containing d to the left, all other terms to the right

3d=2

d=2/3

d=2/3

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