4(2d-4)+12=4d+2(6+2d)

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Solution for 4(2d-4)+12=4d+2(6+2d) equation:



4(2d-4)+12=4d+2(6+2d)
We move all terms to the left:
4(2d-4)+12-(4d+2(6+2d))=0
We add all the numbers together, and all the variables
4(2d-4)-(4d+2(2d+6))+12=0
We multiply parentheses
8d-(4d+2(2d+6))-16+12=0
We calculate terms in parentheses: -(4d+2(2d+6)), so:
4d+2(2d+6)
We multiply parentheses
4d+4d+12
We add all the numbers together, and all the variables
8d+12
Back to the equation:
-(8d+12)
We add all the numbers together, and all the variables
8d-(8d+12)-4=0
We get rid of parentheses
8d-8d-12-4=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation

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