4(2d-5)=-20+8d

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Solution for 4(2d-5)=-20+8d equation: 



4(2d-5)=-20+8d

We move all terms to the left:

4(2d-5)-(-20+8d)=0

We add all the numbers together, and all the variables

4(2d-5)-(8d-20)=0

We multiply parentheses

8d-(8d-20)-20=0

We get rid of parentheses

8d-8d+20-20=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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