4(2f+)=2(f-13)

Solution for 4(2f+)=2(f-13) equation:

4(2f+)=2(f-13)

We move all terms to the left:

4(2f+)-(2(f-13))=0

We add all the numbers together, and all the variables

4(+2f)-(2(f-13))=0

We multiply parentheses

8f-(2(f-13))=0


We calculate terms in parentheses: -(2(f-13)), so:

2(f-13)

We multiply parentheses

2f-26

Back to the equation:

-(2f-26)


We get rid of parentheses

8f-2f+26=0

We add all the numbers together, and all the variables

6f+26=0

We move all terms containing f to the left, all other terms to the right

6f=-26

f=-26/6

f=-4+1/3