4(2f+1)=20

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Solution for 4(2f+1)=20 equation: 



4(2f+1)=20

We move all terms to the left:

4(2f+1)-(20)=0

We multiply parentheses

8f+4-20=0

We add all the numbers together, and all the variables

8f-16=0

We move all terms containing f to the left, all other terms to the right

8f=16

f=16/8

f=2

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