4(2f+1)=3(f-3)

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Solution for 4(2f+1)=3(f-3) equation: 



4(2f+1)=3(f-3)

We move all terms to the left:

4(2f+1)-(3(f-3))=0

We multiply parentheses

8f-(3(f-3))+4=0



We calculate terms in parentheses: -(3(f-3)), so:

3(f-3)

We multiply parentheses

3f-9

Back to the equation:

-(3f-9)



We get rid of parentheses

8f-3f+9+4=0

We add all the numbers together, and all the variables

5f+13=0

We move all terms containing f to the left, all other terms to the right

5f=-13

f=-13/5

f=-2+3/5

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