4(2f-6)-6(2f-3)=7

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Solution for 4(2f-6)-6(2f-3)=7 equation: 



4(2f-6)-6(2f-3)=7

We move all terms to the left:

4(2f-6)-6(2f-3)-(7)=0

We multiply parentheses

8f-12f-24+18-7=0

We add all the numbers together, and all the variables

-4f-13=0

We move all terms containing f to the left, all other terms to the right

-4f=13

f=13/-4

f=-3+1/4

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