4(2h+2)-2(h+8)=2(h-8)-4

Solution for 4(2h+2)-2(h+8)=2(h-8)-4 equation:

4(2h+2)-2(h+8)=2(h-8)-4

We move all terms to the left:

4(2h+2)-2(h+8)-(2(h-8)-4)=0

We multiply parentheses

8h-2h-(2(h-8)-4)+8-16=0


We calculate terms in parentheses: -(2(h-8)-4), so:

2(h-8)-4

We multiply parentheses

2h-16-4

We add all the numbers together, and all the variables

2h-20

Back to the equation:

-(2h-20)


We add all the numbers together, and all the variables

6h-(2h-20)-8=0

We get rid of parentheses

6h-2h+20-8=0

We add all the numbers together, and all the variables

4h+12=0

We move all terms containing h to the left, all other terms to the right

4h=-12

h=-12/4

h=-3