4(2h+3)=2(5h-2)+6;h

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Solution for 4(2h+3)=2(5h-2)+6;h equation: 



4(2h+3)=2(5h-2)+6h

We move all terms to the left:

4(2h+3)-(2(5h-2)+6h)=0

We multiply parentheses

8h-(2(5h-2)+6h)+12=0



We calculate terms in parentheses: -(2(5h-2)+6h), so:

2(5h-2)+6h

We add all the numbers together, and all the variables

6h+2(5h-2)

We multiply parentheses

6h+10h-4

We add all the numbers together, and all the variables

16h-4

Back to the equation:

-(16h-4)



We get rid of parentheses

8h-16h+4+12=0

We add all the numbers together, and all the variables

-8h+16=0

We move all terms containing h to the left, all other terms to the right

-8h=-16

h=-16/-8

h=+2

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