4(2h-2)+3=2(h+1)+5

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Solution for 4(2h-2)+3=2(h+1)+5 equation: 



4(2h-2)+3=2(h+1)+5

We move all terms to the left:

4(2h-2)+3-(2(h+1)+5)=0

We multiply parentheses

8h-(2(h+1)+5)-8+3=0



We calculate terms in parentheses: -(2(h+1)+5), so:

2(h+1)+5

We multiply parentheses

2h+2+5

We add all the numbers together, and all the variables

2h+7

Back to the equation:

-(2h+7)



We add all the numbers together, and all the variables

8h-(2h+7)-5=0

We get rid of parentheses

8h-2h-7-5=0

We add all the numbers together, and all the variables

6h-12=0

We move all terms containing h to the left, all other terms to the right

6h=12

h=12/6

h=2

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