4(2h-3)-7h=6(h-2)-6(h-1)

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Solution for 4(2h-3)-7h=6(h-2)-6(h-1) equation: 



4(2h-3)-7h=6(h-2)-6(h-1)

We move all terms to the left:

4(2h-3)-7h-(6(h-2)-6(h-1))=0

We add all the numbers together, and all the variables

-7h+4(2h-3)-(6(h-2)-6(h-1))=0

We multiply parentheses

-7h+8h-(6(h-2)-6(h-1))-12=0



We calculate terms in parentheses: -(6(h-2)-6(h-1)), so:

6(h-2)-6(h-1)

We multiply parentheses

6h-6h-12+6

We add all the numbers together, and all the variables

-6

Back to the equation:

-(-6)



We add all the numbers together, and all the variables

h-6=0

We move all terms containing h to the left, all other terms to the right

h=6

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