4(2i+j)+3(i-j)=

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Solution for 4(2i+j)+3(i-j)= equation:


Simplifying
4(2i + j) + 3(i + -1j) = 0
(2i * 4 + j * 4) + 3(i + -1j) = 0
(8i + 4j) + 3(i + -1j) = 0
8i + 4j + (i * 3 + -1j * 3) = 0
8i + 4j + (3i + -3j) = 0

Reorder the terms:
8i + 3i + 4j + -3j = 0

Combine like terms: 8i + 3i = 11i
11i + 4j + -3j = 0

Combine like terms: 4j + -3j = 1j
11i + 1j = 0

Solving
11i + 1j = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1j' to each side of the equation.
11i + 1j + -1j = 0 + -1j

Combine like terms: 1j + -1j = 0
11i + 0 = 0 + -1j
11i = 0 + -1j
Remove the zero:
11i = -1j

Divide each side by '11'.
i = -0.09090909091j

Simplifying
i = -0.09090909091j

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