4(2k-8)=k+1

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Solution for 4(2k-8)=k+1 equation: 



4(2k-8)=k+1

We move all terms to the left:

4(2k-8)-(k+1)=0

We multiply parentheses

8k-(k+1)-32=0

We get rid of parentheses

8k-k-1-32=0

We add all the numbers together, and all the variables

7k-33=0

We move all terms containing k to the left, all other terms to the right

7k=33

k=33/7

k=4+5/7

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