4(2l+1)=68

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Solution for 4(2l+1)=68 equation: 



4(2l+1)=68

We move all terms to the left:

4(2l+1)-(68)=0

We multiply parentheses

8l+4-68=0

We add all the numbers together, and all the variables

8l-64=0

We move all terms containing l to the left, all other terms to the right

8l=64

l=64/8

l=8

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