4(2l+10)=128

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Solution for 4(2l+10)=128 equation:


Simplifying
4(2l + 10) = 128

Reorder the terms:
4(10 + 2l) = 128
(10 * 4 + 2l * 4) = 128
(40 + 8l) = 128

Solving
40 + 8l = 128

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 8l = 128 + -40

Combine like terms: 40 + -40 = 0
0 + 8l = 128 + -40
8l = 128 + -40

Combine like terms: 128 + -40 = 88
8l = 88

Divide each side by '8'.
l = 11

Simplifying
l = 11

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