4(2m+2)+2=20

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Solution for 4(2m+2)+2=20 equation: 



4(2m+2)+2=20

We move all terms to the left:

4(2m+2)+2-(20)=0

We add all the numbers together, and all the variables

4(2m+2)-18=0

We multiply parentheses

8m+8-18=0

We add all the numbers together, and all the variables

8m-10=0

We move all terms containing m to the left, all other terms to the right

8m=10

m=10/8

m=1+1/4

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