4(2m+2)+5(3m-5)=190

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Solution for 4(2m+2)+5(3m-5)=190 equation: 



4(2m+2)+5(3m-5)=190

We move all terms to the left:

4(2m+2)+5(3m-5)-(190)=0

We multiply parentheses

8m+15m+8-25-190=0

We add all the numbers together, and all the variables

23m-207=0

We move all terms containing m to the left, all other terms to the right

23m=207

m=207/23

m=9

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