4(2m-3)=10m+12-2(m+12)

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Solution for 4(2m-3)=10m+12-2(m+12) equation:



4(2m-3)=10m+12-2(m+12)
We move all terms to the left:
4(2m-3)-(10m+12-2(m+12))=0
We multiply parentheses
8m-(10m+12-2(m+12))-12=0
We calculate terms in parentheses: -(10m+12-2(m+12)), so:
10m+12-2(m+12)
determiningTheFunctionDomain 10m-2(m+12)+12
We multiply parentheses
10m-2m-24+12
We add all the numbers together, and all the variables
8m-12
Back to the equation:
-(8m-12)
We get rid of parentheses
8m-8m+12-12=0
We add all the numbers together, and all the variables
=0
m=0/1
m=0

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