4(2m-3)=m-12+7m

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Solution for 4(2m-3)=m-12+7m equation: 



4(2m-3)=m-12+7m

We move all terms to the left:

4(2m-3)-(m-12+7m)=0

We add all the numbers together, and all the variables

4(2m-3)-(8m-12)=0

We multiply parentheses

8m-(8m-12)-12=0

We get rid of parentheses

8m-8m+12-12=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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