4(2m-5)=2(3m-4)-2m

Solution for 4(2m-5)=2(3m-4)-2m equation:

4(2m-5)=2(3m-4)-2m

We move all terms to the left:

4(2m-5)-(2(3m-4)-2m)=0

We multiply parentheses

8m-(2(3m-4)-2m)-20=0


We calculate terms in parentheses: -(2(3m-4)-2m), so:

2(3m-4)-2m

We add all the numbers together, and all the variables

-2m+2(3m-4)

We multiply parentheses

-2m+6m-8

We add all the numbers together, and all the variables

4m-8

Back to the equation:

-(4m-8)


We get rid of parentheses

8m-4m+8-20=0

We add all the numbers together, and all the variables

4m-12=0

We move all terms containing m to the left, all other terms to the right

4m=12

m=12/4

m=3