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4(2m-7)=3(2m/4)
We move all terms to the left:
4(2m-7)-(3(2m/4))=0
We add all the numbers together, and all the variables
4(2m-7)-(3(+2m/4))=0
We multiply parentheses
8m-(3(+2m/4))-28=0
We multiply all the terms by the denominator
8m*4))-(3(+2m-28*4))=0
We add all the numbers together, and all the variables
8m*4))-(3(2m-112))=0
We add all the numbers together, and all the variables
8m*4))-(3(2m=0
Wy multiply elements
32m^2=0
a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:m=\frac{-b}{2a}=\frac{0}{64}=0
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