4(2m-8)=1/7(49m+70)

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Solution for 4(2m-8)=1/7(49m+70) equation: 



4(2m-8)=1/7(49m+70)

We move all terms to the left:

4(2m-8)-(1/7(49m+70))=0



Domain of the equation: 7(49m+70))!=0

m∈R



We multiply parentheses

8m-(1/7(49m+70))-32=0

We multiply all the terms by the denominator


8m*7(49m+70))-(1-32*7(49m+70))=0

Wy multiply elements

56m^2(4-224m(4=0

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